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91 lines
2.7 KiB
Python
91 lines
2.7 KiB
Python
5 years ago
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#-----------------------------------------------------------------
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# pycparser: __init__.py
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#
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# This package file exports some convenience functions for
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# interacting with pycparser
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#
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# Eli Bendersky [https://eli.thegreenplace.net/]
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# License: BSD
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#-----------------------------------------------------------------
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__all__ = ['c_lexer', 'c_parser', 'c_ast']
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__version__ = '2.20'
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import io
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from subprocess import check_output
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from .c_parser import CParser
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def preprocess_file(filename, cpp_path='cpp', cpp_args=''):
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""" Preprocess a file using cpp.
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filename:
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Name of the file you want to preprocess.
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cpp_path:
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cpp_args:
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Refer to the documentation of parse_file for the meaning of these
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arguments.
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When successful, returns the preprocessed file's contents.
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Errors from cpp will be printed out.
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"""
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path_list = [cpp_path]
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if isinstance(cpp_args, list):
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path_list += cpp_args
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elif cpp_args != '':
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path_list += [cpp_args]
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path_list += [filename]
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try:
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# Note the use of universal_newlines to treat all newlines
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# as \n for Python's purpose
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text = check_output(path_list, universal_newlines=True)
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except OSError as e:
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raise RuntimeError("Unable to invoke 'cpp'. " +
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'Make sure its path was passed correctly\n' +
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('Original error: %s' % e))
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return text
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def parse_file(filename, use_cpp=False, cpp_path='cpp', cpp_args='',
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parser=None):
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""" Parse a C file using pycparser.
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filename:
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Name of the file you want to parse.
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use_cpp:
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Set to True if you want to execute the C pre-processor
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on the file prior to parsing it.
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cpp_path:
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If use_cpp is True, this is the path to 'cpp' on your
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system. If no path is provided, it attempts to just
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execute 'cpp', so it must be in your PATH.
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cpp_args:
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If use_cpp is True, set this to the command line arguments strings
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to cpp. Be careful with quotes - it's best to pass a raw string
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(r'') here. For example:
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r'-I../utils/fake_libc_include'
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If several arguments are required, pass a list of strings.
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parser:
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Optional parser object to be used instead of the default CParser
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When successful, an AST is returned. ParseError can be
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thrown if the file doesn't parse successfully.
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Errors from cpp will be printed out.
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"""
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if use_cpp:
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text = preprocess_file(filename, cpp_path, cpp_args)
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else:
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with io.open(filename) as f:
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text = f.read()
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if parser is None:
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parser = CParser()
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return parser.parse(text, filename)
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