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108 lines
4.0 KiB
Python
108 lines
4.0 KiB
Python
5 years ago
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import os
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import errno
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from . import _common
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from ._compat import FileNotFoundError
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from io import BytesIO, TextIOWrapper, open as io_open
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def open_binary(package, resource):
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"""Return a file-like object opened for binary reading of the resource."""
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resource = _common.normalize_path(resource)
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package = _common.get_package(package)
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# Using pathlib doesn't work well here due to the lack of 'strict' argument
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# for pathlib.Path.resolve() prior to Python 3.6.
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package_path = os.path.dirname(package.__file__)
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relative_path = os.path.join(package_path, resource)
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full_path = os.path.abspath(relative_path)
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try:
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return io_open(full_path, 'rb')
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except IOError:
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# This might be a package in a zip file. zipimport provides a loader
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# with a functioning get_data() method, however we have to strip the
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# archive (i.e. the .zip file's name) off the front of the path. This
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# is because the zipimport loader in Python 2 doesn't actually follow
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# PEP 302. It should allow the full path, but actually requires that
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# the path be relative to the zip file.
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try:
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loader = package.__loader__
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full_path = relative_path[len(loader.archive)+1:]
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data = loader.get_data(full_path)
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except (IOError, AttributeError):
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package_name = package.__name__
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message = '{!r} resource not found in {!r}'.format(
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resource, package_name)
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raise FileNotFoundError(message)
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return BytesIO(data)
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def open_text(package, resource, encoding='utf-8', errors='strict'):
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"""Return a file-like object opened for text reading of the resource."""
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return TextIOWrapper(
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open_binary(package, resource), encoding=encoding, errors=errors)
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def read_binary(package, resource):
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"""Return the binary contents of the resource."""
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with open_binary(package, resource) as fp:
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return fp.read()
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def read_text(package, resource, encoding='utf-8', errors='strict'):
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"""Return the decoded string of the resource.
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The decoding-related arguments have the same semantics as those of
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bytes.decode().
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"""
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with open_text(package, resource, encoding, errors) as fp:
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return fp.read()
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def path(package, resource):
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"""A context manager providing a file path object to the resource.
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If the resource does not already exist on its own on the file system,
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a temporary file will be created. If the file was created, the file
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will be deleted upon exiting the context manager (no exception is
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raised if the file was deleted prior to the context manager
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exiting).
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"""
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path = _common.files(package).joinpath(_common.normalize_path(resource))
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if not path.is_file():
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raise FileNotFoundError(path)
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return _common.as_file(path)
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def is_resource(package, name):
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"""True if name is a resource inside package.
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Directories are *not* resources.
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"""
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package = _common.get_package(package)
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_common.normalize_path(name)
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try:
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package_contents = set(contents(package))
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except OSError as error:
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if error.errno not in (errno.ENOENT, errno.ENOTDIR):
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# We won't hit this in the Python 2 tests, so it'll appear
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# uncovered. We could mock os.listdir() to return a non-ENOENT or
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# ENOTDIR, but then we'd have to depend on another external
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# library since Python 2 doesn't have unittest.mock. It's not
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# worth it.
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raise # pragma: nocover
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return False
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if name not in package_contents:
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return False
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return (_common.from_package(package) / name).is_file()
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def contents(package):
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"""Return an iterable of entries in `package`.
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Note that not all entries are resources. Specifically, directories are
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not considered resources. Use `is_resource()` on each entry returned here
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to check if it is a resource or not.
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"""
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package = _common.get_package(package)
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return list(item.name for item in _common.from_package(package).iterdir())
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