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61 lines
2.2 KiB
Haskell
61 lines
2.2 KiB
Haskell
import Data.List (sort, sortBy)
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import AllNames (names)
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compareSurnameWithCompareFunction :: (Ord a1, Ord a2) => (a1, a2) -> (a1, a2) -> Ordering
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compareSurnameWithCompareFunction name1 name2 = if result == EQ
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then compare forename1 forename2
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else result
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where surname1 = snd name1
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surname2 = snd name2
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forename1 = fst name1
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forename2 = fst name2
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result = compare surname1 surname2
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compareSurname :: Ord a1 => (a2, a1) -> (a3, a1) -> Ordering
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compareSurname name1 name2 = if surname1 > surname2
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then GT
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else if surname1 < surname2
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then LT
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else EQ
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where surname1 = snd name1
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surname2 = snd name2
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compareFullName :: (Ord a1, Ord a2) => (a2, a1) -> (a2, a1) -> Ordering
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compareFullName name1 name2 = if surname1 > surname2
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then GT
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else if surname1 < surname2
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then LT
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else if forename1 > forename2
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then GT
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else if forename1 < forename2
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then LT
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else EQ
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where surname1 = snd name1
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surname2 = snd name2
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forename1 = fst name1
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forename2 = fst name2
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{- Using Guards for boolean expressions
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compareSurname :: Ord a1 => (a2, a1) -> (a3, a1) -> Ordering
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compareSurname name1 name2
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| surname1 > surname2 = GT
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| surname1 < surname2 = LT
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| otherwise = EQ
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where
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surname1 = snd name1
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surname2 = snd name2
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compareFullName :: (Ord a1, Ord a2) => (a2, a1) -> (a2, a1) -> Ordering
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compareFullName name1 name2
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| lastName1 > lastName2 = GT
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| lastName1 < lastName2 = LT
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| firstName1 > firstName2 = GT
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| firstName1 < firstName2 = LT
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| otherwise = EQ
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where
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lastName1 = snd name1
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lastName2 = snd name2
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firstName1 = fst name1
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firstName2 = fst name2
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-} |