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40 lines
1.3 KiB
Markdown
40 lines
1.3 KiB
Markdown
3 years ago
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# signal-exit
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[![Build Status](https://travis-ci.org/tapjs/signal-exit.png)](https://travis-ci.org/tapjs/signal-exit)
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[![Coverage](https://coveralls.io/repos/tapjs/signal-exit/badge.svg?branch=master)](https://coveralls.io/r/tapjs/signal-exit?branch=master)
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[![NPM version](https://img.shields.io/npm/v/signal-exit.svg)](https://www.npmjs.com/package/signal-exit)
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[![Standard Version](https://img.shields.io/badge/release-standard%20version-brightgreen.svg)](https://github.com/conventional-changelog/standard-version)
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When you want to fire an event no matter how a process exits:
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* reaching the end of execution.
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* explicitly having `process.exit(code)` called.
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* having `process.kill(pid, sig)` called.
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* receiving a fatal signal from outside the process
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Use `signal-exit`.
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```js
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var onExit = require('signal-exit')
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onExit(function (code, signal) {
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console.log('process exited!')
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})
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```
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## API
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`var remove = onExit(function (code, signal) {}, options)`
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The return value of the function is a function that will remove the
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handler.
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Note that the function *only* fires for signals if the signal would
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cause the process to exit. That is, there are no other listeners, and
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it is a fatal signal.
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## Options
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* `alwaysLast`: Run this handler after any other signal or exit
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handlers. This causes `process.emit` to be monkeypatched.
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